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1)Two massive particles of masses M and m (M>m) are separated by a distance L. They rotate with equal angular velocity under their gravitational attraction. What is the linear speed of the particle of mass m?
As the body is moving in circular path, so according to the newton's second law,the force is acting towards the center of masses and the acceleration is centripetal i.e. F(g)=ma=mv^2/r------------(i) where r is the radius of circular path and v = linear speed of body
F(g)= gravitational force = GMm/L^2-------------(ii)
Not yet studied gravitation at filter
ReplyDeleteWill answer when I learn gravitation properly
As the body is moving in circular path, so according to the newton's second law,the force is acting towards the center of masses and the acceleration is centripetal
ReplyDeletei.e.
F(g)=ma=mv^2/r------------(i)
where r is the radius of circular path and v = linear speed of body
F(g)= gravitational force = GMm/L^2-------------(ii)
equate (i) and (ii) we get
mv^2/r=GMm/L^2
v^2/r=GM/L^2
v^2=GMr/L^2
v=1/L x √GMr